b^2+49+14b+b^2=25

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Solution for b^2+49+14b+b^2=25 equation:


Simplifying
b2 + 49 + 14b + b2 = 25

Reorder the terms:
49 + 14b + b2 + b2 = 25

Combine like terms: b2 + b2 = 2b2
49 + 14b + 2b2 = 25

Solving
49 + 14b + 2b2 = 25

Solving for variable 'b'.

Reorder the terms:
49 + -25 + 14b + 2b2 = 25 + -25

Combine like terms: 49 + -25 = 24
24 + 14b + 2b2 = 25 + -25

Combine like terms: 25 + -25 = 0
24 + 14b + 2b2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(12 + 7b + b2) = 0

Factor a trinomial.
2((4 + b)(3 + b)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(4 + b)' equal to zero and attempt to solve: Simplifying 4 + b = 0 Solving 4 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + b = 0 + -4 b = 0 + -4 Combine like terms: 0 + -4 = -4 b = -4 Simplifying b = -4

Subproblem 2

Set the factor '(3 + b)' equal to zero and attempt to solve: Simplifying 3 + b = 0 Solving 3 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + b = 0 + -3 Combine like terms: 3 + -3 = 0 0 + b = 0 + -3 b = 0 + -3 Combine like terms: 0 + -3 = -3 b = -3 Simplifying b = -3

Solution

b = {-4, -3}

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